알고리즘/프로그래머스
[파이썬][프로그래머스] Lv. 1 실패율
SBOX Learning by doing
2022. 6. 21. 21:18
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def solution(N, stages):
result = {}
denominator = len(stages)
for stage in range(1, N+1):
if denominator != 0:
count = stages.count(stage)
result[stage] = count / denominator
denominator -= count
else:
result[stage] = 0
return sorted(result, key=lambda x : result[x], reverse=True)
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