알고리즘/프로그래머스

[파이썬][프로그래머스] Lv. 1 실패율

SBOX Learning by doing 2022. 6. 21. 21:18
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def solution(N, stages):
    result = {}
    denominator = len(stages)
    for stage in range(1, N+1):
        if denominator != 0:
            count = stages.count(stage)
            result[stage] = count / denominator
            denominator -= count
        else:
            result[stage] = 0
    return sorted(result, key=lambda x : result[x], reverse=True)

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